# A tram car with a mass of 16 tons moves along a horizontal track at a speed of 6 m / s.

September 27, 2021 | education

| **A tram car with a mass of 16 tons moves along a horizontal track at a speed of 6 m / s. What is the braking force to stop the car at a distance of 10 m?**

To determine the required braking force for stopping a tram car, we will use the formula: Ftorm = m * a = m * Vn ^ 2 / 2S.

The values of the variables: m is the mass of the tram car (m = 16 t = 16 * 10 ^ 3 kg); Vн – the speed of the car before braking (Vн = 6 m / s); S – required braking distance (S = 10 m).

Calculation: Ftorm = m * Vn ^ 2 / 2S = 16 * 10 ^ 3 * 6 ^ 2 / (2 * 10) = 28.8 * 10 ^ 3 H = 28.8 kN.

Answer: To stop a tram car, the braking force must be 28.8 kN.

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