A tram moving at a speed of 12m / s starts braking which is equal to its stopping distance if it stops after 8s.
| June 10, 2021 | education
To find the value of the stopping distance of the tram under consideration, we use the formula: S = (Vn – Vk) * t / 2 = (Vn – 0) * t / 2.
Variables: Vн – initial speed of the tram (Vн = 12 m / s); t is the duration of inhibition (t = 8 s).
Calculation: S = Vн * t / 2 = 12 * 8/2 = 48 m.
Answer: The braking distance of the tram in question is 48 meters.
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