A tram moving from a stop with an acceleration of 0.6 m / s covered a distance of 30 meters, what is the speed?
| August 7, 2021 | education
Initial data: the tram started moving from a stop (V0 (initial speed) = 0 m / s); a (tram acceleration) = 0.6 m / s2; S (the path that the tram traveled) = 30 m.
The speed of the tram at the end of a given path is determined from the formula: S = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2a, whence V = √ (S * 2a).
Calculation: V = √ (30 * 2 * 0.6) = 6 m / s.
Answer: At the end of the given path, the speed of the tram was 6 m / s.
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