A tram with a current of 110A and a voltage of 380V develops a traction force of 3kN

| May 11, 2021 | education

A tram with a current of 110A and a voltage of 380V develops a traction force of 3kN. How fast it will move along the horizontal path. if the efficiency of the electric heater is 60%.

I = 110 A.

U = 380 V.

Ftyag = 3 kN = 3000 N.

Efficiency = 60%.

V -?

Let us write down the formula for the efficiency of the tram: Efficiency = Apol * 100% / Azat, where Apol is the useful work of the tram, Azat is the work expended, the work of the electric current in the engine.

The expended work of the Azat current is expressed by the Joule-Lenz law: Azatr = I * U * t, where I is the current strength, U is the voltage, t is the time of passage of the current.

The useful work of Apol is expressed by the formula: Apol = Ftyag * S, where Ftyag is the thrust force of the engine, S is the movement of the tram.

Efficiency = Ftyag * S * 100% / I * U * t = Ftyag * V * 100% / I * U.

V = S / t.

Tram speed V will be determined by the formula: V = efficiency * I * U / Ftyag * 100%.

V = 60% * 110 A * 220 V / 3000 N * 100% = 4.84 m / s.

Answer: the tram is moving at a speed of V = 4.84 m / s.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.