A tram with a mass of 20 tons, departing from the stop, at a distance of 50 m, developed a speed
| June 21, 2021 | education
A tram with a mass of 20 tons, departing from the stop, at a distance of 50 m, developed a speed of 8 / m / s. Determine the traction force of tram engines.
To determine the value of the traction force of the engines of a given tram, we will use the formula: Ftyag = m * a = m * Vk ^ 2 / 2S.
Variables: m is the mass of the tram (m = 20 t = 2 * 10 ^ 4 kg); Vк – the speed reached by the tram (Vк = 8 m / s); S – distance traveled (S = 50 m).
Calculation: Ftyag = m * Vk ^ 2 / 2S = 2 * 10 ^ 4 * 8 ^ 2 / (2 * 50) = 12.8 * 10 ^ 3 H = 12.8 kN.
Answer: The thrust force of the engines of a given tram is 12.8 kN.
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