A transformer with 110 turns in the secondary winding lowers the voltage from 22 kV to 220 V.

A transformer with 110 turns in the secondary winding lowers the voltage from 22 kV to 220 V. how many turns the primary winding contains.

To find the number of turns in the primary winding of the used transformer, we apply the equality: N1 / N2 = Un / Uk, from where we express: N1 = Un * N2 / Uk.

Variables: Un – initial voltage, primary winding (Un = 22 kV = 22 * 10 ^ 3 V); N2 – turns of the secondary winding (N2 = 110 pcs.); Uк – final voltage, secondary winding (Uк = 220 V).

Calculation: N1 = Un * N2 / Uk = 22 * 10 ^ 3 * 110/220 = 11 * 10 ^ 3 turns.

Answer: The primary winding of the used transformer must contain 11 * 103 turns.



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