A trapezoid ABCD is inscribed in a circle of radius R with an acute angle at the base AD equal to a.
A trapezoid ABCD is inscribed in a circle of radius R with an acute angle at the base AD equal to a. It is known that the bisector of angle C passes through the center of the circumscribed circle. Find the area of the trapezoid
Since the trapezoid is inscribed in a circle, it is isosceles.
Since the OC is the bisector of the ВСD angle, the angle AСD = OСВ = ВСD / 2.
The OСD triangle is isosceles, since OС = OD = R.
Then the angle ODС = OСD, which means the angle ODС = OСD, and therefore the angle ВСD = 2 * ODС.
Let the angle ODС = X, then BCD= 2 * X.
X + 2 * X = 180.
X = ODС = 60.
ВСD angle = 120.
Then the triangle OСD is equilateral, OС = OD = СD = R = AD / 2 = a / 2.
The ВOС triangle is also equilateral, since OB = OB = R, and the angle ВOС = AOB = 600, then BC = OС / 2.
The area of a trapezoid is equal to the sum of three equilateral triangles with side a.
Streug = a2 * √3 / 4 cm2.
Strap = 3 * Streug = 3 * a ^ 2 * √3 / 4 cm2.
Answer: The area of the trapezoid is 3 * a2 * √3 / 4 cm2.