A triangle whose perimeter is 30 is divided by the bisector into two triangles

A triangle whose perimeter is 30 is divided by the bisector into two triangles, the perimeters of which are 16 and 24. Find the bisector of this triangle

The sum of the perimeters of two triangles into which the bisector splits this triangle is equal to the perimeter of this triangle in the sum with twice the length of the bisector. That is, if x is the length of the bisector, then

30 + 2x = 16 + 24, whence

2x = 10,

x = 5.

Answer: 5.



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