A triangle with two sides equal to 24 cm and 12√3 cm. inscribed in a circle with a radius of 12 cm. Determine the angles of the triangle.
February 23, 2021 | education
| Let us apply the sine theorem for a triangle inscribed in a circle.
AC / SinABC = 2 * R.
SinABC = AC / 2 * R = 12 * √3 / 2 * 12 = √3 / 2.
Angle ABC = arcsin (√3 / 2) = 60.
AB / SinACB = 2 * R.
SinACB = AB / 2 * R = 24/2 * 12 = 1.
Angle ACB = arcsin (1) = 90.
Then the angle BAC = (180 – 90 – 60) = 30.
Answer: The angles of the inscribed triangle are 30, 60, 90.
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