A trolley weighing 10 kg is moved 6 m on a smooth horizontal surface while doing 120J of work.

A trolley weighing 10 kg is moved 6 m on a smooth horizontal surface while doing 120J of work. With what acceleration does the cart move, if it is. was the initial velocity zero?

Given:

m = 10 kilograms – the mass of the cart, which is moved along a smooth horizontal surface;

h = 6 meters – distance to move the cart;

A = 120 Joules – the work that is done to move the cart.

It is required to determine a (m / s2) – the trolley acceleration.

Let’s find the force with which the cart is moved:

F = A / h = 120/6 = 20 Newtons.

Then, in order to determine the acceleration of the cart, it is necessary to use the following formula (Newton’s second law):

F = m * a;

a = F / m;

a = 20/10 = 2 m / s2.

Answer: the cart is moved with an acceleration equal to 2 m / s2.