A trolley weighing 15 kg moves at a speed of 4 m / s. After collision with a stationary bogie weighing 5 kg.
| January 3, 2021 | education
A trolley weighing 15 kg moves at a speed of 4 m / s. After collision with a stationary bogie weighing 5 kg. The carts move together. Determine how fast the carts move together.
To calculate the speed of the joint motion of the given bogies, we use the equality (the law of conservation of momentum, an inelastic collision is considered): (mt1 + mt2) * Vt12 = mt1 * Vt1, whence we express: Vt12 = mt1 * Vt1 / (mt1 + mt2).
Variables: mt1 – mass of the movable carriage (mt1 = 15 kg); Vt1 – the speed of the mobile cart before inelastic collision (Vt1 = 4 m / s); mt2 is the mass of the initially stationary bogie (mt2 = 5 kg).
Calculation: VT12 = 15 * 4 / (15 + 5) = 3 m / s.
Answer: The carts will have to move at a speed of 3 m / s.
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