A trolley weighing 150kg moves along a horizontal road at a speed of 1m, s. He runs towards her at a speed of 1.4 m

A trolley weighing 150kg moves along a horizontal road at a speed of 1m, s. He runs towards her at a speed of 1.4 m, with a man weighing 75 kg and jumps onto a cart. What is the speed of the cart.

To find the speed with which the used cart will continue its movement, we will use the equality (law of conservation of momentum, oncoming traffic): mt * Vt – mh * Vh = (mt + mh) * Vtch, whence we express: Vtch = (mt * Vt – mh * Vh) / (mt + mh).

Variables: mt – bogie weight (mt = 150 kg); Vt – trolley speed (Vt = 1 m / s); mh – human weight (mh = 75 kg); Vh – running speed of a person (Vh = 1.4 m / s).

Calculation: Vtch = (150 * 1 – 75 * 1.4) / (150 + 75) = 0.2 m / s.

Answer: The cart should continue its movement at a speed of 0.2 m / s.