A trolley weighing 40 kg moves along the rails at a speed of 1 m / s. A man weighing 60 kg runs towards her at a speed of 0.5 m / s. Determine the speed of the cart after the person jumps into it.
m1 = 40 kg – trolley weight;
v1 = 1 m / s – trolley speed;
m2 = 60 kg – human weight;
v2 = 0.5 m / s – human speed.
It is required to find v3 – the speed of the cart after a person jumps into it.
According to the law of conservation of momentum:
m1 * v1 – m2 * v2 = (m1 + m2) * v3
40 * 1 – 60 * 0.5 = 100 * v3
40 – 30 = 100 * v3 or from here:
v3 = 10/100 = 0.1 m / s.
Answer: the trolley speed will be 0.1 m / s.
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