A trolley weighing 50kg moves horizontally at a speed of 2m / s. A person jumps off the cart at a speed

| June 25, 2021 | education

A trolley weighing 50kg moves horizontally at a speed of 2m / s. A person jumps off the cart at a speed of 4 m / s relative to the ground in the direction opposite to the movement of the cart. The mass of a person is 70 kg. What is the speed of the cart after the person has jumped off it?

To determine the speed at which the used cart will continue to move, we use the equality: mt * Vt – mh * Vh = Vtch * (mt + mh), from where we express: Vt = (Vtch * (mt + mh) + mh * Vh) / Vt …

Variables: Vtch – initial trolley speed (Vtch = 2 m / s); mt – bogie weight (mt = 50 kg); mh – the mass of the jumped off person (mh = 70 kg); Vh – the speed of a person’s jump (Vh = 4 m / s).

Calculation: Vt = (2 * (50 + 70) + 70 * 4) / 50 = 10.4 m / s.

Answer: After a person has jumped, the trolley used will acquire a speed of 10.4 m / s.



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