A trolley with a mass of 2 kg moving at a speed of 3 m / h collides with a stationary trolley with
| December 13, 2020 | education
A trolley with a mass of 2 kg moving at a speed of 3 m / h collides with a stationary trolley with a mass of 4 kg and engages with it determine the speed of movement of the trolley after interaction
According to the law of conservation of momentum for collision with adhesion:
m1v1 + m2v2 = (m1 + m2) v
v2 = 0, therefore, m1v1 = (m1 + m2) v, whence
v = m1v1 / (m1 + m2) = 2 * 4 / (2 + 4) = 8/6 = 4/3
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