A trolleybus weighing 12 tons starts to move with an acceleration of 0.5 m / s2.

A trolleybus weighing 12 tons starts to move with an acceleration of 0.5 m / s2. What traction force does the trolleybus motor develop during this movement, if we consider the movement to be uniformly accelerated, and take the friction force equal to 2500 N.

To determine the magnitude of the traction force of the motor of the trolleybus under consideration, we will project all the forces on the axis of movement of the trolleybus: m * a = Ftraction – Ftren, whence Ftraction = m * a + Ftren.

The values of the variables: m is the mass of the considered trolleybus (m = 12 t = 12 * 10 ^ 3 kg); a – constant acceleration (a = 0.5 m / s2); Ftren – friction force (Ftren = 2500 N).

Calculation: Fthroat = m * a + Ftren = 12 * 10 ^ 3 * 0.5 + 2500 = 8.5 * 10 ^ 3 H = 8.5 kN.

Answer: The thrust of the motor of the trolleybus in question is 8.5 kN.