A trolleybus with a mass of 10 tons, starting off on a path of 50 m, acquired a speed of 10 m / s.

| April 25, 2021 | education

A trolleybus with a mass of 10 tons, starting off on a path of 50 m, acquired a speed of 10 m / s. Determine the operation of the engine, if the friction coefficient is 0.04, and the power developed by the trolleybus.

To find the operation of the trolleybus engine and the power it develops, we use the formulas: A = F * S = (m * a + Ftr) = (m * a + μ * m * g) * S = (m * V ^ 2 / 2S + μ * m * g) * S and N = A / t = A / (V / a) = A * (V ^ 2 / S) / V = ​​A * V / S.

Variables and constants: m is the mass of the trolleybus (m = 10 t = 10 ^ 4 kg); V is the acquired speed (V = 10 m / s); S – trolleybus path (S = 50 m); μ – coefficient of friction (μ = 0.04); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: a) Work: A = (m * V ^ 2 / 2S + μ * m * g) * S = (10 ^ 4 * 10 ^ 2 / (2 * 50) + 0.04 * 10 ^ 4 * 10 ) * 50 = 200 * 10 ^ 3 J = 200 kJ;

b) Power: N = A * V / S = 200 * 10 ^ 3 * 10/50 = 40 * 10 ^ 3 W = 40 kW.

Answer: The work of the trolleybus engine is 200 kJ, the power is 40 kW.



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