A truck crane lifts a load weighing 2 tons to a height of 10 m. What kind of work does it do?

These tasks: m (weight of the cargo lifted by the truck crane) = 2 t (in SI m = 2000 kg); h (lifting height) = 10 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The work performed by the used truck crane can be represented as a change in the potential energy of the load, and calculated by the formula: A = ΔEp = m * g * h.

Let’s calculate: A = 2000 * 10 * 10 = 200 * 10 ^ 3 J or 200 kJ.

Answer: When lifting the load, the used truck crane performed a work of 200 kJ.