A truck left town A at 8 o’clock in the morning at a speed of 32 km / h, and at 11 o’clock in the afternoon

A truck left town A at 8 o’clock in the morning at a speed of 32 km / h, and at 11 o’clock in the afternoon a bus followed it at a speed of 56 km / h. At what time and at what distance from the city will the bus catch up with the truck?

Let both the truck and the bus go x km, then the truck was on the way x / 32 hours, and the bus – x / 56 hours. It is known that the truck was on the way for more (x / 32 – x / 56) hours or (11 – 8) hours. Let’s make an equation and solve it.
x / 32 – x / 56 = 11 – 8;
x / 32 – x / 56 = 3 – bring the left side of the equation to a common denominator 224;
(7x) / 224 – (4x) / 224 = 3;
(7x – 4x) / 224 = 3;
3x = 3 * 224;
x = (3 * 224) / 3;
x = 224 (km) – distance from city A, at which the bus will catch up with the truck.
Find out how long the truck was on the way. The path must be divided into speed. 224: 32 = 7 (h).
If the truck left at 8 o’clock, and was on the road for 7 hours, before the time when the bus caught up with it. So the bus caught up with the truck at 8 + 7 = 15 hours.
Answer. 224 km, at 15 o’clock.