A tungsten ingot has a mass of 1 kg. What will the volume ratio be if it is smelted into an aluminum

A tungsten ingot has a mass of 1 kg. What will the volume ratio be if it is smelted into an aluminum one without losing mass?

To find the value of the ratio of the volumes of aluminum and tungsten ingots, we use the formula: k = Vа / Vв = (m / ρа) / (m / ρв) = ρв / ρа.

Constants: ρw – density of tungsten (by condition ρw = 19300 kg / m3); ρа – density of aluminum (by condition ρа = 2700 kg / m3).

Calculation: k = ρv / ρа = 19300/2700 = 7.15 p.

Answer: An aluminum ingot will have 7.15 times the volume.



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