A turn of a wire with an area of 20 cm2 is closed to a capacitor with a capacity of 20 μF. The plane of the loop

A turn of a wire with an area of 20 cm2 is closed to a capacitor with a capacity of 20 μF. The plane of the loop is perpendicular to the induction line of a uniform magnetic field. Determine the rate of change of the modulus of the magnetic field induction line delta V / delta t, if the charge on the capacitor is 2.0 μC.

To calculate the value of the rate of change of the magnetic field induction, we use the formula (we take into account that by the condition sinα = 1): εi = -S * dВ / dt, whence we express: dВ / dt = εi / S = q / (C * S).

Variables: q is the charge on the capacitor (q = 2 μC = 2 * 10 ^ -6 C); C is the capacitance of the capacitor to which the loop is closed (C = 20 μF = 2 * 10 ^ -5 F); S is the area of the wire coil (S = 20 cm2 = 2 * 10 ^ -3 m2).

Let’s make a calculation: dВ / dt = q / (C * S) = 2 * 10 ^ -6 / (2 * 10 ^ -5 * 2 * 10 ^ -3) = 50 T / s.

Answer: The induction of the magnetic field changes at a rate of 50 T / s.