A two-digit number is greater than the product of its digits by 12. Find this number.

Let this number be ab, then this number in the sum of the bit terms can be written as:

10a + b.

Since, according to the condition of the problem, the product of its digits is 12 more than the number itself, then the following equation can be drawn up:

b + 10a – 12 = a * b. Find by selecting the numbers a and b.

Let’s take b = 1, then a + 10 – 12 = 2a → a = 10 – 12 = -2, this is an incorrect front position.

Let’s take b = 2, then a + 20 – 12 = 2a → a = 20 – 12 = 8.

Let’s check: 28 – 12 = 16 = 2 * 6.

Let’s take b = 3, then a + 30 – 12 = 2a → a = 30 – 12 = 18, the second number is a two-digit number, which means this is an incorrect assumption.

Therefore, the research can be stopped at this, because with b = 4 and higher, the second number will not be unambiguous.

Answer: Number 28.