A vector AB with an end at point B (-10. -2) has coordinates (-22, 2) find the abscissa a.

Vector AB.

A {x1; y1} – the beginning of the vector;

B {-10; -2} – end of vector;

AB {-22; 2}.

1) Find the length of the vector AB.

d = √ (x ^ 2 + y ^ 2) = √ (-22) ^ 2 + 2 ^ 2) = √ (484 + 4) = √488;

2) Vector AB has coordinates {x2 – x1; y2 – y1}.

{-22; 2} = {-10 – x1; 2 – y1};

Since, you need to find the abscissa of the vector A, then we get:

-22 = -10 – x1;

-22 + 10 = -x1;

-x1 = -22 + 10;

-x1 = -12;

x1 = 12;

Answer: the abscissa of vector A is 12.