A vehicle weighing 5 tons is moving at a constant speed. find the thrust force of the engine

A vehicle weighing 5 tons is moving at a constant speed. find the thrust force of the engine if the friction force is 0.005 of its mass …

m = 5 t = 5000 kg.

g = 10 m / s2.

V = const.

Ftr = 0.005 * R.

Fт -?

Since the car moves uniformly in a straight line, then, according to 1 Newton’s law, the action of forces on it is compensated: Ft + m * g + N + Ftr = 0.

Where Ft is the vehicle’s traction force, m * g is the gravity force, N is the reaction force of the road surface, Ftr is the friction force.

OH: 0 = Ft – Ftr.

OU: 0 = – m * g + N.

We see that when driving, the traction force of the car Ft is compensated by the friction force Ftr: Ft = Ftr.

P = m * g.

Ft = 0.005 * 5000 kg * 10 m / s2 = 250 N.

The condition of the problem is not written correctly, the friction force is 0.005 of its weight, not its mass.

Answer: the thrust force of the engine is Ft = 250 N.