A vertical metal rod 50 cm long moves horizontally at a speed of 3 m / s in a uniform magnetic

| June 18, 2021 | education

A vertical metal rod 50 cm long moves horizontally at a speed of 3 m / s in a uniform magnetic field with an induction of 0.15 T. The lines of magnetic induction of the field are directed horizontally at right angles to the direction of the velocity vector of the rod. What is the EMF of the induction in the rod?

To find the value of the EMF in the specified vertical metal rod, we use the formula: ε = B * V * l * sinα.

Variables: B – field induction (B = 0.15 T); V is the speed of movement of the specified rod (V = 3 m / s); l is the length of the rod (l = 50 cm = 0.5 m); α is the angle between the velocity vector of the specified rod and the field induction lines (α = 90º).

Let’s calculate: ε = B * V * l * sinα = 0.15 * 3 * 0.5 * sin 90º = 0.225 V.

Answer: EMF of induction in the specified rod is equal to 0.225 V.



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