A vessel with a capacity of 2 • 10 – 3 m3 is filled with nitrogen under a pressure of 2 • 10-5 Pa at a temperature of 127 ° C.
A vessel with a capacity of 2 • 10 – 3 m3 is filled with nitrogen under a pressure of 2 • 10-5 Pa at a temperature of 127 ° C. Determine the mass of oxygen in the vessel if its molar mass is 0.032 kg / mol
V = 2 * 10-3 m3.
P = 2 * 10-5 Pa.
M (O2) = 0.032 kg / mol.
R = 8.31 m2 * kg / s2 * ° K * mol.
T = 400 ° K.
m -?
Let us write down the Mendeleev-Cliperon equation for oxygen in the cylinder: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the mass of oxygen in the cylinder, R is the universal gas constant, T is the absolute temperature gas, M is the molar mass of the gas.
m = P * V * M / R * T.
We express the absolute temperature of oxygen T by the formula: T = t + 273 = 127 ° C + 273 = 400 ° K.
m = 2 * 10-5 Pa * 2 * 10-3 m3 * 0.032 kg / mol / 8.31 m2 * kg / s2 * ° K * mol * 400 ° K = 3.5 * 10-13 kg.
Answer: the vessel contains m = 3.5 * 10-13 kg of oxygen.