A voltage of 200V is applied to a circuit consisting of three resistors with resistances R1 = 10Ω, R2 = 30Ω, R3 = 20Ω
A voltage of 200V is applied to a circuit consisting of three resistors with resistances R1 = 10Ω, R2 = 30Ω, R3 = 20Ω. Determine the current strength in each resistor, the resistance of the circuit, the voltage across the first and second resistors. Determine the power consumed by the circuit and the energy consumption for 6 hours of operation.
Let’s find the total resistance Ro of three series-connected resistors R1 = 10 Ohm, R2 = 30 Ohm, R3 = 20 Ohm:
Ro = R1 + R2 + R3 = 10 + 30 + 20 = 60 ohms.
Find the current flowing through the circuit if the voltage is U = 200 V:
I = U / Ro = 200/60 = 3.33 A.
Let’s find the voltage across the first resistor:
U1 = I * R1 = 3.33 * 10 = 33.3 V.
Let’s find the voltage across the second resistor:
U2 = 3.33 * 30 = 99.9 B.
Let’s find the total power of the circuit:
P = U * I = 200 * 3.33 = 666 W.
Let’s find the energy consumption for the time t = 6 hours:
A = P * t = 666 * 6 = 3996 W * h ≈ 4 kW * h.