A voltmeter with a resistance of 8 kohm, designed for a voltage of 120 V.
| May 25, 2021 | education
A voltmeter with a resistance of 8 kohm, designed for a voltage of 120 V. Calculate the current in the voltmeter winding at the moment when its arrow deviated to the end of the scale?
Task data: R (voltmeter resistance) = 8 kOhm (8 * 10 ^ 3 Ohm); U (maximum voltage for which the considered voltmeter is designed) = 120 V.
The strength of the current in the winding of the voltmeter, when its arrow has deviated to the end of the scale, can be calculated using Ohm’s law for a section of the circuit: I = U / R.
Let’s make a calculation: I = 120 / (8 * 10 ^ 3) = 15 * 10 ^ -3 A = 15 mA.
Answer: The current in the voltmeter winding was 15 mA.
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