A wagon with sand with a total mass of 20 tons by inertia by a horizontal section of a railway track

A wagon with sand with a total mass of 20 tons by inertia by a horizontal section of a railway track at a speed of 2 m / s. 5 tons of sand falls into the car and remains in it. Determine the speed of the car after the fall of this portion of sand.

The joint speed of the car and the portion of sand can be calculated using the law of conservation of momentum:

m1V1 + m2V2 = (m1 + m2) V1.2, where m1 is the own weight of the car (m1 = 20 t), V1 is the own speed of the car (V1 = 2 m / s), m2 is the mass of a portion of sand (m2 = 5 t ), V2 is the initial speed of a portion of sand (V2 = 0 m / s), V1.2 is the speed of a car with sand.

V1.2 = m1 * V1 / (m1 + m2) = 20 * 2 / (20 + 5) = 40/25 = 1.6 m / s.

Answer: The speed of the car after the fall of a portion of sand is 1.6 m / s.



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