A water drop with an electric charge q 1 = 2 nC joined with another drop with a charge q2 = – 4 nC.

A water drop with an electric charge q 1 = 2 nC joined with another drop with a charge q2 = – 4 nC. Then the formed drop will be divided into 2 identical drops. find the charges formed by the drops.

To find the values of the charges of the formed droplets, we will use the equality: q1 + q2 = const = q1.2 / 2, whence we express: q1.2 = (q1 + q2) / 2.

Values of variables: q1 – initial charge of the first water drop (q1 = 2 nC); q2 is the initial charge of the second water droplet (q2 = -4 nC).

Let’s calculate: q1.2 = (q1 + q2) / 2 = (2 + (-4)) / 2 = -1 nC.

Answer: Each of the formed drops will have a charge of -1 nC.