A wave 3 m long propagates over the water surface in the lake at a speed of 6 m / s, causing the float to oscillate.

A wave 3 m long propagates over the water surface in the lake at a speed of 6 m / s, causing the float to oscillate. Determine the vibration frequency of the float.

The period T is the reciprocal of the frequency N, that is, T = 1 / N
Now into the formula
L (lambda) = V * T
We substitute this formula, display and find the frequency
And it turns out
N = V / L
N = 6/3 = 2 (Hz)
Answer: N = 2 (Hz)



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