A wave with an oscillation period of 4 s propagates at a speed of 3.2 m / s. What is the phase shift between two points
A wave with an oscillation period of 4 s propagates at a speed of 3.2 m / s. What is the phase shift between two points of the wave lying on the same ray, if the distance between them and the source is 40 cm and 60 cm, respectively.
To find the value of the phase shift between the two indicated points, we use the formula: Δφ = 2 * Π * Δt / T = 2 * Π * Δl / (T * V) = 2 * Π * (l2 – l1) / (T * V).
Variables: l2 – distance between the source and the second point (l2 = 60 cm = 0.6 m); l1 is the distance between the source and the first point (l1 = 40 cm = 0.4 m); T – wave period (T = 4 s); V – wave speed (V = 3.2 m / s).
Calculation: Δφ = 2 * Π * (0.6 – 0.4) / (4 * 3.2) = Π / 32 rad.
Answer: The phase shift between the two indicated points is Π / 32 rad.