A weighed portion of magnesium weighing 0.6713 was dissolved in hydrochloric acid. How much hydrogen will be released in this case?

The reaction between magnesium and hydrochloric acid proceeds with the formation of magnesium chloride and the evolution of hydrogen. The reaction equation can be written as:

Mg + 2 HCl = MgCl2 + H2

The molar mass of magnesium is 24 g / mol. The molar volume of gases is a constant value at normal conditions. and is equal to 22.4 l / mol (according to Avogadro’s law).

Let’s make a proportion according to the reaction equation:

0.6713 g of magnesium corresponds to X l. hydrogen like

24 g / mol magnesium corresponds to 22.4 l / mol hydrogen

X = (0.6713 * 22.4) / 24 = 0.6265 l.

Answer: 0.6265 l. hydrogen