A weight of 100 kg is suspended on the short arm of the lever. To lift it, a force equal to 250 N was applied to the long shoulder.
| November 30, 2020 | education
A weight of 100 kg is suspended on the short arm of the lever. To lift it, a force equal to 250 N was applied to the long shoulder. The load was lifted to a height of 0.08m. At the same time, the point of application of the driving force dropped by 0.04m. Find the lever efficiency.
decision
Efficiency = Ap / Ac = mgh1 / Fh2 = (100 × 10 × 0.08) / (250 × 0.04) = 8
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