A weight of 100 kg was attached to the right arm of the 50 cm long lever. How much force must

A weight of 100 kg was attached to the right arm of the 50 cm long lever. How much force must be applied to the 2.5m left arm to balance the arm?

These tasks: lp (length of the right shoulder) = 50 cm (in SI lp = 0.5 m); mp (weight of the load on the first shoulder) = 100 kg; ll (left shoulder length) = 2.5 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The force that will need to be applied to the left shoulder of the lever taken can be expressed from the equality: Fl * ll = Fp * lp = mp * g * lp, whence Fl = mp * g * lp / lp.

Let’s make a calculation: Fl = 100 * 10 * 0.5 / 2.5 = 200 N.

Answer: A force of 200 N is required to the left arm of the lever.