A weight of 2 kg fixed on a spring with a stiffness of 200 N / m. spring tension was ..

According to Newton’s third law, the spring force will be balanced by the force of gravity.
Fcont. = Fт., Where Fcont. = k * ∆l (k is the stiffness of the spring, k = 200 N / m, ∆l = the amount of deformation (tension)), Ft = m * g (m is the mass of the load (m = 2 kg), g is the acceleration of gravity (we take g = 10 m / s ^ 2)).
Then:
Fcont. = Fт. = k * ∆l = m * g.
Let us express the tension of the spring:
∆l = m * g / k = 2 * 10/200 = 0.1 m.
Check: m = (kg * m / s ^ 2) / (N / m) = (kg * m ^ 2 / s ^ 2) / (kg * m / s ^ 2) = m.
Answer. The deformation of the spring is 0.1 m.