A weight of 200 g is rotated uniformly in a vertical plane on a 0.6 m long rope at a speed of 1.5 m / s.

A weight of 200 g is rotated uniformly in a vertical plane on a 0.6 m long rope at a speed of 1.5 m / s. What is the tension force of the rope when the load passes the upper and lower points of the trajectory?

Decision:
a = v ^ 2 / R = 2.25: 0.6 = 3.75 m / s ^ 2
F1 = m (a-g) = 0.2 * -6.25 = -1.25H
F2 = 0.2 * 13.75 = 2.75H
Answer: -1.25 N; 2.75 N



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