A weight of 700 N was attached to the arm at a distance of 40 cm from the fulcrum.

| June 17, 2021 | education

A weight of 700 N was attached to the arm at a distance of 40 cm from the fulcrum. How much force must be applied on the other side of the lever at a distance of 80 cm to keep the lever in balance?

F1 = 700 N.

l1 = 40 cm = 0.4 m.

l2 = 80 cm = 0.8 m.

F2 -?

The condition for the balance of the lever is the equality of the moments of forces: M1 = M2.

The moment of force M is the product of the force F to the smallest distance from the application of force to the axis of balance, which is called the shoulder l: M = F * l.

M1 = F1 * l1.

M2 = F2 * l2.

F1 * l1 = F2 * l2.

The formula for determining the applied force F2 to the lever will take the form: F2 = F1 * l1 / l2.

F2 = 700 N * 0.4 m / 0.8 m = 350 N.

Answer: to balance the lever, you need to apply a force F2 = 350 N.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.