A weight weighing 0.4 kg vibrates on the spring. The spring rate is 40N / m. how many vibrations does
| February 26, 2021 | education
A weight weighing 0.4 kg vibrates on the spring. The spring rate is 40N / m. how many vibrations does the load make in 1 minute?
Data: m (weight of the load on a spring pendulum) = 0.4 kg; k (spring rate of the pendulum) = 40 N / m; t (duration of oscillation of the load) = 1 min (60 s).
1) Determine the period of oscillation of the load on the spring: T = 2Π * √ (m / k) = 2 * 3.14 * √ (0.4 / 40) = 0.628 s.
2) Let’s calculate the number of oscillations of the load in 1 minute: n = t / T = 60 / 0.628 = 95.54 oscillations (95 complete oscillations).
Answer: In 1 minute, the load will make 95 complete vibrations.
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