A wet snowball was lowered into the calorimeter with 1 liter of water. Snow mass – 250g

A wet snowball was lowered into the calorimeter with 1 liter of water. Snow mass – 250g, initial water temperature – 20 degrees. After the snow melted, the water temperature in the calorimeter became 5 degrees. How much water was in the wet snow?

There is no data on the calorimeter (mass, material); therefore, we neglect its mass. Since snow is said to be wet, it is at 0 degrees and consists of ice and water. It is the mass of this water that needs to be found. The heat balance equation will contain the equality of the amounts of heat spent on melting the ice contained in the snow (it is not necessary to heat it to the melting temperature, it is already at 0 degrees) + the heat that went into heating the water that was in the snow, and that from ice formed after melting, up to 5 degrees (steady temperature). And all this is equal to the amount of heat given up by the water cooling from 20 degrees to 5. We find the mass of water in the calorimeter by multiplying its volume (1 l = 1 cubic dm) by the density = 1 kg.