# A wire 10 cm long with a diameter of 0.1 mm breaks under the action of a load weighing 1 kg.

A wire 10 cm long with a diameter of 0.1 mm breaks under the action of a load weighing 1 kg. What mass will the load break a wire 20 cm long with a diameter of 0.2 mm?

Given: l1 (length of the first wire) = 10 cm; d1 (diameter of the first wire) = 0.1 mm; m1 (mass of the first load) = 1 kg; l2 (length of the second wire) = 20 cm; d2 (second wire diameter) = 0.2 mm.

To find the mass of the load that will break the second wire, we will use the formula for calculating the ultimate tensile strength: Ϭw = P1 / F1 = P2 / F2; m1 * g / (0.25 * Π * d1 ^ 2) = m2 * g / (0.25 * Π * d2 ^ 2) and m2 = m1 * d2 ^ 2 / d1 ^ 2.

Calculation: m2 = 1 * 0.2 ^ 2 / 0.12 = 4 kg.

Answer: The wire will be torn by a weight of 4 kg. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.