A wire with a resistance of 25 ohms was cut into 5 identical parts, which were twisted with a bundle.
| January 12, 2021 | education
A wire with a resistance of 25 ohms was cut into 5 identical parts, which were twisted with a bundle. What is the resistance of this harness?
Let’s calculate the resistance of one part (for which we divide the total resistance by 5):
25/5 = 5 ohms.
Since these parts are twisted into a bundle, their beginnings and ends will be common, that is, they are connected in parallel. When connected in parallel, the conductivity is added, then the total resistance will be:
R = 1 / (1/5 + 1/5 + 1/5 + 1/5 + 1/5) = 1 Ohm.
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