A woman with blond hair married a man with dark curly hair. What is the probability of having a baby

A woman with blond hair married a man with dark curly hair. What is the probability of having a baby with blond curly hair if the genes that determine the recessive traits (blond and straight hair) are localized on different chromosomes, and the man is heterozygous for both traits?

Let’s designate the gene that causes the development of light-colored hair in humans as c, then the gene for dark hair will be designated as C.
Let us designate the gene responsible for the development of straight hair as p, and the gene for curly hair as P.
Most likely, the statement of the problem implies that the blonde woman has straight hair. Its genotype, according to the introduced designations, will be written as ccrr, because recessive traits can be realized in the phenotype only if the genotype of their owner is homozygous for the genes that determine them.
The female ccpp produces cp oocytes.
A man, according to the condition, is diheterozygous – CcPp. It produces four types of sperm – cp, cp, cp and cp.
The offspring of this married couple are represented by the following theoretically possible options:
children with light straight hair (ccpp) – 25%;
children with dark curly hair (СсРp) – 25%;
children with dark straight hair (Ссpp) – 25%;
children with light curly hair (ccpp) – 25%.
Answer: There is a 25% chance of having a baby with blond curly hair.