A woman with blue eyes married a heterozygous man with brown eyes. Determine the possible genotypes of children.

If a man has brown eyes and is heterozygous, then brown eye color is the dominant trait. Because in such a genotype it is the action of the dominant gene that is manifested. Then the blue-eyed woman will be homozygous by genotype.

Let K – brown eyes, then k – blue.

RR g kk (g) x m Kk (k)

m / f K k k Kk (k) kk (g) k Kk (k) kk (g)
By phenotype:

50% brown eyes, 50% blue eyes.

Answer: in this family, the probability of having blue-eyed and brown-eyed children is the same, that is, 1: 1.