A wooden block in the form of a rectangular parallelepiped is 5.5 dm long, 2.6 dm wide, and 1.2 dm high.

A wooden block in the form of a rectangular parallelepiped is 5.5 dm long, 2.6 dm wide, and 1.2 dm high. Weight of 1 dm 3 of a cube tree 0.7 kg. Find the mass of the block of wood.

1) First, let’s calculate the volume of a wooden block (V), which has the shape of a rectangular parallelepiped with sides a = 5.5 dm, b = 2.6 dm and h = 1.2 dm:
V = a * b * h = 5.5 * 2.6 * 1.2 = 17.16 dm ^ 3.
2) Let the mass of a wooden block, the volume of which is 17.16 dm ^ 3, be equal to x kg.
3) Let’s write:
1 dm ^ 3 – 0.7 kg;
17.16 dm ^ 3 – x kg.
4) From here we compose and solve the proportion:
1: 17.16 = 0.7: x;
1 * x = 17.16 * 0.7;
x = 12.012.
5) Having decided the proportion, we find that the mass of this wooden block is 12.012 kg.
Answer: 12.012 kg.