A wooden block weighing 50 g lies on a wooden board. Is it possible to move it from its place by applying

A wooden block weighing 50 g lies on a wooden board. Is it possible to move it from its place by applying a force equal to 0.25 N to it in the horizontal direction? The maximum resting friction coefficient of wood against wood is approximately 0.6.

Given:

m = 50 grams is the mass of a wooden block;

g = 9.8 m / s2 – acceleration of gravity;

k = 0.6 is the coefficient of the resting friction force of the tree against the tree;

F = 0.25 Newton – the force applied to move the bar.

It is required to determine whether the force F can move the bar from its place.

In order to move the body from its place, it is necessary to apply to it a force greater than the force of friction at rest.

Let us find the static friction force for the bar.

F rest = k * N = k * m * g = 0.6 * 9.8 * 0.05 = 6 * 0.05 = 0.29 Newton.

Since F rest> F (0.29> 0.25), the bar cannot be moved.

Answer: the bar cannot be moved with the help of force 0.25 Newton.