A wooden block with a mass of m = 1 kg was lowered into a vessel with water with an area of S = 700 cm2.

A wooden block with a mass of m = 1 kg was lowered into a vessel with water with an area of S = 700 cm2. Determine the difference in water levels in the vessel (in mm) before and after immersing the bar.

S = 700 cm ^ 2 = 0.07 m ^ 2.
m = 1 kg.
ρ = 700 kg / m ^ 3.
Δh -?
When a wooden block is immersed, the water rises up to the volume of this block.
Let’s find the volume of a wooden block V = m / ρ.
Let us express this volume in terms of the area of the vessel S and the height Δh to which the water in the vessel rises.
V = S * Δh.
m / ρ = S * Δh.
Δh = m / ρ * S.
Δh = 1 kg / 700 kg / m ^ 3 * 0.07 m ^ 2 = 0.02 m = 20 mm.
Answer: the difference in water levels in the vessel is Δh = 20 mm.