A worker, using a movable block with an efficiency equal to 70%, evenly lifts a load weighing 63 kg

A worker, using a movable block with an efficiency equal to 70%, evenly lifts a load weighing 63 kg to the tenth floor of a house under construction. Find the force with which the worker pulls on the rope thrown over the block. Acceleration of free fall is taken equal to 10N / kg.

Tasks given: movable unit; uniform movement; η (unit efficiency) = 70% (0.7); m (cargo weight) = 63 kg.

Constants: by condition g (acceleration of gravity) = 10 N / kg.

To find the applied labor force, we use the formula: η = Ap / Az = m * g * h / (F * S) = m * g * h / (F * 2h) = m * g / 2F and F = m * g / 2η.

Calculation: F = 63 * 10 / (2 * 0.7) = 450 N.

Answer: The worker in question pulls the rope with a force of 450 N.



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