A zinc ingot weighing 2.5 kg heated to a temperature of 420 degrees
| February 6, 2021 | education
A zinc ingot weighing 2.5 kg heated to a temperature of 420 degrees is transferred at the same temperature to a liquid state. How much energy is required for this?
Initial data: m (mass of zinc ingot) = 2.5 kg; the zinc ingot is at the melting temperature (t = 420 ºC).
Constants: λ (specific heat of fusion of zinc) = 122 kJ / kg = 122 * 10 ^ 3 J / kg.
The required amount of energy for melting the zinc ingot is calculated by the formula: Q = λ * m.
Let’s perform the calculation: Q = 122 * 10 ^ 3 * 2.5 = 305 * 10 ^ 3 J = 305 kJ.
Answer: In order to convert a zinc ingot into a liquid state, 305 kJ of thermal energy is required.
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