AB = BC, angle B = 80 degrees, find the rest.

If in a triangle two sides are equal to each other, then this triangle is isosceles. In an isosceles triangle, the angles at the base are equal to each other. Since it is said that AB = BC, then the side of the base is AC, therefore, the angles adjacent to this side:

∠A = ∠C.

If the angle between equal sides is known, that is, ∠B, any of the angles at the base is found:

(180 ° – 80 °) / 2 = 50 °, therefore, ∠A = ∠С = 50 °.



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